उत तर:
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))) ((1) / (((x + 4))) ((x) ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) / ((एक स ^ 2 + 4) (ln (x ^ 2 + 4)))) #
स पष ट करण:
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4))))) (1 / (((x + 4) / (ln (x ^ 2 + 4))))) (((1) (ln (x ^ 2 + 4)) -। (x + 4) (1) / ((एक स ^ 2 + 4)) (2x)) / ((ln (x ^ 2 + 4))) ^ 2) #
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))) (ln (x ^ 2 + 4) / (((x + 4))) । ((ln (x ^ 2 + 4) - (2x ^ 2 + 4x) / ((एक स ^ 2 + 4))) / ((ln (x ^ 2 + 4))) ^ 2) #
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4))))) (रद द कर (ln (x ^ 2 + 4)) / ((x + 4)))) (((एक स ^ 2 + 4) (ln (x ^ 2 + 4)) -। (2x ^ 2 + 4x)) / ((एक स ^ 2 + 4) (ln (x ^ 2 + 4)) ^ रद द (2))) #
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))) ((1) / (((x + 4))) ((x) ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) / ((एक स ^ 2 + 4) (ln (x ^ 2 + 4)))) #
