उत तर: (x + 2) स पष ट करण: # एफ (एक स) = (ए / ब) / (स / ड) # X क सभ क र य: 1. # ए = 3x ^ 2 - 7x -6 = # (3x + 2) (x - 3) 2. # ब = x ^ 3 - 3x ^ 2 + 4x - 12 = (x - 3) (x ^ 2 + 4) # 3. # स = 3x ^ 2 - 4x - 4 = # (3x + 2) (x - 2) 4. #d = x ^ 4 - 16 = (x ^ 2 + 4) (x - 2) (x + 2) # #f (x) = (3x + 2) (x - 3) / (x - 3) (x ^ 2 + 4) (x ^ 2 + 4) (x - 2) (x + 2)) / (3x + 2) (x - 2) # f (x) = (x + 2)
