उत तर:
# (d ^ 2ln (x ^ 2 + 4)) / dx ^ 2 = (8 - 2x ^ 2) / (x ^ 2 + 4) ^ 2 #
स पष ट करण:
श र खल न यम ह:
# (d {f (u (x))}) / dx = (df (u)) / (du) ((du) / dx) #
चल #u (x) = x ^ 2 + 4 #, फ र # (df (u)) / (du) = (dln (u)) / (du) = 1 / u # तथ # (du) / dx = 2x #
# (dln (x ^ 2 + 4)) / dx = (2x) / (x ^ 2 + 4) #
# (d ^ 2ln (x ^ 2 + 4)) / dx ^ 2 = (d ((2x) / (x ^ 2 + 4)) / dx #
# (d ((2x) / (x ^ 2 + 4)) / dx = #
{{2 (x ^ 2 + 4) - 2x (2x)} / (x ^ 2 + 4) ^ 2 = #
# (8 - 2x ^ 2) / (x ^ 2 + 4) ^ 2 #
