यद f (x) = sin ^ 3x और g (x) = sqrt (3x-1, f) क य ह (g (x))?

#F (x) = प प ^ 3x #, # D_f = आरआर #

#G (x) = sqrt (3x-1) #, # मह न द शक = 1/3, + ऊ) #

#D_ (क हर) = {## AAX ## म ##RR: ##एक स## म ## D_g #, #G (एक स) ## म ##D_f} #

#x> = 1/3 #, #sqrt (3x-1) ## म ## आरआर # #-># #एक स## म ## 1/3, + ऊ) #

# AAX ## म ## 1/3, + ऊ) #,

# (क हर) '(x) = च' (g (x)) ज '(x) = च' (sqrt (3x-1)) ((3x-1) ') / (2sqrt (3x-1)) #

#F '(x) = 3sin ^ 2x (sinx)' = 3sin ^ 2xcosx #

इसल ए # (क हर) '(x) = प प ^ 2 (sqrt (3x-1)) cos (sqrt (3x-1)) * 9 / (2sqrt (3x-1)) #

क य ह (sqrt (5+) sqrt (3)) / (sqrt (3+) sqrt (3+) sqrt (5)) - (sqrt (5-) sqrt (3)) / (sqrt (3+) sqrt (3) sqrt (5))?

2/7 हम ल त ह , A = (sqrt5 + sqrt3) / (sqrt3 + sqrt3 + sqrt5) - (sqrt5-sqrt3) / (sqrt3 + sqrt3-sqrt5) = (sqrt5 + sqrt3) / (2sqrt3 + sqrt5) - (sqrt5 + sqrt3) -sqrt3) / ((2sqrt3-sqrt5) = (sqrt5 + sqrt3) / (2sqrt3 + sqrt5) - (sqrt5-sqrt3) / (2sqrt3-sqrt5) = ((sqrt5 + sqrt3) - (sqrt5 + sqrt3) (2sqrt3-sqrt5) - (sqrt5 + sqrt5) ) (2sqrt3 + sqrt5)) / ((2sqrt3 + sqrt5) (2sqrt3-sqrt5) = ((2sqrt15-5 + 2 * 3-sqrt15) - (2sqrt15 + 5-2 * 3-sqrt15)) ((2sqrt3) ^ 2- (sqrt5) ^ 2) = (रद द कर (2sqrt15) -5 + 2 * 3cancel (-sqrt15) - रद द कर (2sqrt15) -5 + 2 * 3 + रद द (sqrt15) = (12-5) = ( -10 + 12) / 7 = 2/7 ध य न द क , यद भ जक म ह (sqrt3 +

आप क स सरल करत ह (1 / sqrt (a-1) + sqrt (a + 1)) / (1 / sqrt (a + 1) -1 / sqrt (a-1)) div sqrt (a + 1) / ( (a-1) sqrt (a + 1) - (a + 1) sqrt (a-1)), a> 1?

व श ल गण त प र र पण ...> र ग (न ल ) (((1 / sqrt (a-1) + sqrt (a + 1)) / (1 / sqrt (a + 1) -1 / sqrt (a-1)) ) / (sqrt (a + 1) / ((a-1) sqrt (a + 1) - (a + 1) sqrt (a-1)) = color (ल ल) ((1 / sqrt (a) 1) + sqrt (a + 1)) / ((sqrt (a-1) -sqrt (a + 1)) / (sqrt (a + 1) cdot sqrt (a-1))) / (sqrt ( +1) / (sqrt (a-1) cdot sqrt (a-1) cdot sqrt (a + 1) -sqrt (a + 1) cdot sqrt (a + 1) sqrt (a-1)) (र ग) न ल ) (((1 / sqrt (a-1) + sqrt (a + 1)) / ((sqrt (a-1) -sqrt (a + 1)) / (sqrt (a + 1) cdot sqrt (a) -1))) / (sqrt (a + 1) / (sqrt (a + 1) cdot sqrt (a-1) (sqrt (a-1) -sqrt (a + 1)) = color (ल ल) ((1 / sqrt (a-1) + sqrt (a + 1)) / ((sq

अभ व यक त क सरल बन ए ?: 1 / (sqrt (144) + sqrt (145)) + 1 / (sqrt (145) + sqrt (146)) + ... + 1 / (sqrt (168) + sqrt (169))

1 पहल न ट क : 1 / (sqrt (n + 1) + sqrt (n)) = (sqrt (n + 1) -sqrt (n)) / ((sqrt (n + 1) + sqrt (n)) () sqrt (n + 1) -sqrt (n)) र ग (सफ द) (1 / (sqrt (n + 1) + sqrt (n)) = (sqrt (n + 1) -sqrt (n)) / () n + 1) -n) र ग (सफ द) (1 / (sqrt (n + 1) + sqrt (n)) = sqrt (n + 1) -sqrt (n) So: 1 / (sqrt (144) +) sqrt (145)) + 1 / (sqrt (145) + sqrt (146)) + ... + 1 / (sqrt (168) + sqrt (169)) = (sqrt (145) -sqrt (144)) + (sqrt (146) -sqrt (145)) + ... + (sqrt (169) -sqrt (168)) = sqrt (169) -sqrt (144) = 13-12 = 1