क य ह (sqrt (5+) sqrt (3)) / (sqrt (3+) sqrt (3+) sqrt (5)) - (sqrt (5-) sqrt (3)) / (sqrt (3+) sqrt (3) sqrt (5))?

क य ह (sqrt (5+) sqrt (3)) / (sqrt (3+) sqrt (3+) sqrt (5)) - (sqrt (5-) sqrt (3)) / (sqrt (3+) sqrt (3) sqrt (5))?
Anonim

उत तर:

#2/7#

स पष ट करण:

हम ल त ह, # एक = (sqrt5 + sqrt3) / (sqrt3 + sqrt3 + sqrt5) - (sqrt5-sqrt3) / (sqrt3 + sqrt3-sqrt5) #

# = (Sqrt5 + sqrt3) / (2sqrt3 + sqrt5) - (sqrt5-sqrt3) / (2sqrt3-sqrt5) #

# = (Sqrt5 + sqrt3) / (2sqrt3 + sqrt5) - (sqrt5-sqrt3) / (2sqrt3-sqrt5) #

# = ((sqrt5 + sqrt3) (2sqrt3-sqrt5) - (sqrt5-sqrt3) (2sqrt3 + sqrt5)) / ((2sqrt3 + sqrt5) (2sqrt3-sqrt5) # 2

# = ((2sqrt15-5 + 2 * 3-sqrt15) - (2sqrt15 + 5-2 * 3-sqrt15)) / ((2sqrt3) ^ 2- ((sqrt5) ^ 2) #

# = (रद द कर (2sqrt15) -5 + 2 * 3cancel (-sqrt15) - रद द कर (2sqrt15) -5 + 2 * 3 + रद द (sqrt15)) / (12-5) #

#=(-10+12)/7#

#=2/7#

ध य न द, यद हर म ह

# (sqrt3 + sqrt (3 + sqrt5)) और (sqrt3 + sqrt (3-sqrt5)) #

त जव ब बदल ज एग ।